Maximum Power Transfer Theorem (RL = RS)
Derivation, worked example, and efficiency trade-offs of the Maximum Power Transfer Theorem, including the AC conjugate-matching case.
Contents & prerequisites
In power electronics, RF matching networks, and signal chain design, engineers constantly face a choice: should a source drive a load for maximum voltage, maximum efficiency, or maximum power? The Maximum Power Transfer Theorem answers the third question precisely, and its condition — load resistance equal to source resistance — shows up everywhere from audio amplifier output stages to antenna matching to sensor interfacing. Understanding when it applies (and when it's the wrong design goal) is a core skill for any circuit designer.
The Theorem
For a linear source with fixed Thevenin equivalent resistance R_S driving a variable resistive load R_L, the power delivered to the load is maximized when:
R_L = R_S
This is a statement about matching a load to a fixed source impedance — it does not mean minimizing losses or maximizing efficiency. Those are different (often conflicting) objectives, discussed below.
Deriving the Condition
Model the source as a Thevenin equivalent: open-circuit voltage V_TH in series with source resistance R_S, driving a load R_L.
V_TH ──[R_S]──┬──[R_L]── ref
│
(load current I flows through both)
Current in the loop:
I = V_TH / (R_S + R_L)
Power delivered to the load:
P_L = I²·R_L = V_TH²·R_L / (R_S + R_L)²
To find the R_L that maximizes P_L, take the derivative with respect to R_L and set it to zero. Using the quotient rule on R_L / (R_S + R_L)²:
dP_L/dR_L = V_TH² · [(R_S + R_L)² − R_L·2(R_S + R_L)] / (R_S + R_L)⁴
= V_TH² · [(R_S + R_L) − 2R_L] / (R_S + R_L)³
= V_TH² · (R_S − R_L) / (R_S + R_L)³
Setting the numerator to zero: R_S − R_L = 0, so R_L = R_S. The second derivative is negative at this point, confirming a maximum (not a minimum or inflection).
Maximum Power Value
Substituting R_L = R_S back into the power expression:
P_max = V_TH²·R_S / (R_S + R_S)² = V_TH²·R_S / (4R_S²) = V_TH² / (4R_S)
This is the single most useful number from the theorem: the maximum power any resistive load can ever extract from a source of Thevenin voltage V_TH and resistance R_S is V_TH²/(4R_S) — independent of what R_L actually is, since R_L is set equal to R_S by construction.
Worked Example
A sensor's Thevenin equivalent is V_TH = 2 V, R_S = 50 Ω. Find the load resistance for maximum power transfer and the resulting power, then verify against two off-match cases.
Matched case, R_L = 50 Ω:
I = 2 / (50 + 50) = 2/100 = 0.02 A
P_L = I²·R_L = (0.02)²·50 = 0.0004·50 = 0.02 W = 20 mW
Check against the formula: P_max = V_TH²/(4R_S) = 4/(200) = 0.02 W. Matches.
Off-match case 1, R_L = 25 Ω (half of R_S):
I = 2 / (50 + 25) = 2/75 = 0.0267 A
P_L = (0.0267)²·25 = 0.000711·25 = 0.0178 W = 17.8 mW
Lower than 20 mW, as expected.
Off-match case 2, R_L = 100 Ω (double R_S):
I = 2 / (50 + 100) = 2/150 = 0.0133 A
P_L = (0.0133)²·100 = 0.000178·100 = 0.0178 W = 17.8 mW
Also 17.8 mW — notice the symmetry: R_L = R_S/2 and R_L = 2R_S give identical (reduced) power, because the power curve is symmetric on a log scale of R_L/R_S. Both confirm the peak at R_L = R_S is a true maximum, not a broad plateau — the power falls off on both sides.
Efficiency at Matched Load Is Only 50%
This is the critical trade-off engineers must internalize. At R_L = R_S, exactly half the total generated power is dissipated in R_S itself (as heat in the source) and half in R_L:
η = P_L / P_total = R_L / (R_S + R_L) = R_S / (2R_S) = 0.5 = 50%
For the worked example: total power delivered by the source is I²·(R_S + R_L) = (0.02)²·100 = 0.04 W, of which 0.02 W goes to R_L and 0.02 W is dissipated in R_S — confirming the 50% split.
This is why maximum power transfer is not the goal in power distribution, battery-powered systems, or any application where efficiency matters. A power supply feeding a load wants R_L ≫ R_S so that nearly all power reaches the load (high efficiency, lower absolute power). Maximum power transfer matters instead in situations where the source can only deliver a small, fixed amount of power and the goal is to extract as much of it as possible — signal chains, RF systems, sensor interfaces, and audio output stages historically matched to speaker impedance.
Reactive (Complex Impedance) Case
For AC circuits with a source impedance Z_S = R_S + jX_S, the theorem generalizes: maximum power transfer occurs when the load impedance is the complex conjugate of the source impedance:
Z_L = Z_S* = R_S − jX_S
The reactive parts cancel (X_S + X_L = 0), leaving a purely resistive net loop at resonance, and the resistive parts satisfy the same R_L = R_S condition derived above. This conjugate-match condition is the basis of RF impedance matching networks (e.g., matching a 50 Ω source to an antenna with reactive components at a specific frequency) and is a generalization students meet after mastering the resistive case.
If the load is constrained to be purely resistive while the source has reactance, the optimal R_L instead equals |Z_S| = √(R_S² + X_S²) — a different (and less commonly needed) result worth noting but not the primary design case.
Practical Design Implications
| Scenario | Design goal | Matching choice |
|---|---|---|
| Battery/power supply → load | Efficiency | R_L ≫ R_S |
| RF transmitter → antenna | Max power transfer, standing-wave minimization | R_L = R_S (typically 50 Ω or 75 Ω systems) |
| Audio amp → speaker (historical, transformer-coupled) | Max power transfer | R_L = R_S |
| Sensor (high output impedance) → ADC input | Signal fidelity, minimal loading | R_L ≫ R_S |
| Transmission line termination | Reflection-free transfer | R_L = Z_0 (characteristic impedance) |
Note that modern audio and most instrumentation systems deliberately avoid matched loading — solid-state amplifiers use low output impedance and high-impedance loads (bridging) specifically to maximize voltage transfer and efficiency, not power transfer. The matched-load convention persists mainly in RF/transmission-line contexts, where R_L = R_S (or more precisely, conjugate matching to Z_0) also prevents signal reflections — a signal integrity concern distinct from, but related to, the power argument.
Key Takeaways
- Maximum power transfer to a resistive load occurs when
R_L = R_S, derived by settingdP_L/dR_L = 0onP_L = V_TH²·R_L/(R_S+R_L)². - The resulting maximum power is
P_max = V_TH²/(4R_S), independent of the specific R_L value once matched. - At the matched condition, efficiency is exactly 50% — half the power is wasted as heat in the source resistance, so this condition is undesirable whenever efficiency (not raw power extraction) is the goal.
- For AC/reactive sources, the general condition is conjugate matching:
Z_L = Z_S*, which cancels reactance and applies the same R_L = R_S rule to the resistive parts. - Use matched loading in RF, transmission-line, and signal-extraction contexts; use mismatched (R_L ≫ R_S) loading in power delivery and most modern voltage-driven amplifier/sensor interfaces.
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